All the resources available on the internet like question banks and previous year papers are easy to come by. What's different here?

Did you know that JEE 2015 question paper is considered to be the toughest paper set since 2005? IIT-Bombay set the 2015 paper.

And, do you know that IIT-Guwahati is setting the JEE-2016 paper? The last time IIT-G had set the JEE paper was in 2009. So we've done some research and found the trickiest questions from the IIT JEE-2009 paper.

Did you know that JEE 2015 question paper is considered to be the toughest paper set since 2005? IIT-Bombay set the 2015 paper.

And, do you know that IIT-Guwahati is setting the JEE-2016 paper? The last time IIT-G had set the JEE paper was in 2009. So we've done some research and found the trickiest questions from the IIT JEE-2009 paper.

**Question #1**

Look at the drawing given in the figure which has been drawn with ink of uniform line-thickness. The mass of ink used to draw each of the two inner circles, and each of the two line segments is m. The mass of the ink used to draw the outer circle is 6m.

The coordinates of the centres of the different parts are: outer circle (0,0), left inner circle (-a,a), right inner circle (a,a), vertical line (0,0) and horizontal line (0, -a). The y-coordinate of the centre of mass of ink in this drawing is

- a/10
- a/8
- a/12
- a/3

Answer for Question #1 : 1) a/10

A disk of radius a/4 having a uniformly distributed charge 6C is placed in the x-y plane with its centre at (-a/2, 0,0). A rod of length

**Question #2**A disk of radius a/4 having a uniformly distributed charge 6C is placed in the x-y plane with its centre at (-a/2, 0,0). A rod of length

*a*carrying a uniformly distributed charge 8C is placed on the x-axis from x=a/4 to x=5a/4. Two point charges -7C and 3C are placed at (a/4, -a/4, 0) and (-3a/4, 3a/4, 0), respectively. Consider a cubical surface formed by six surfaces x = ±a/2, y = ± a/2, z = ±a/2. The electric flux through this cubical surface is- -2C/epsilon naught
- 2C/epsilon naught
- 10C/epsilon naught
- 12C/epsilon naught

Answer for Question #2 : 1) -2C/epsilon naught

Two small particles of equal masses start moving in opposite directions from a point A in a horizontal circular orbit. Their tangential velocities are

**Question #3**Two small particles of equal masses start moving in opposite directions from a point A in a horizontal circular orbit. Their tangential velocities are

*v*and*2v*, respectively, as shown in the figure. Between collisions, the particles move with constant speeds. After making how many elastic collisions, other than that at A, these two particles will again reach the point A?- 4
- 3
- 2
- 1

Answer for Question #3 : 3) 2

Under the influence of the Coulomb field of charge

**Question #4**Under the influence of the Coulomb field of charge

*+Q*, a charge*-q*is moving around it in an elliptical orbit. Find out the correct statements(s).- The angular momentum of the charge
*-q*is constant - The linear momentum of the charge
*-q*is constant - The angular velocity of the charge
*-q*is constant - The linear speed of the charge
*-q*is constant

Answer for Question #4 : 1) The angular momentum of the charge

*-q*is constant

**Question #5**

Two soap bubbles A and B are kept in a closed chamber where the air is maintained at pressure 8 N/m2. The radii of bubbles A and B are 2cm and 4cm, respectively. Surface tension of the soap-water used to make bubbles is 0.04 N/m. Find the ratio

*nB/nA,*where

*nA*and

*nB*are the number of moles of air in bubbles A and B. respectively. [Neglect the effect of gravity.]

Answer for Question #5 : 6

A solid sphere of radius

**Question #6**A solid sphere of radius

*R*has a charge*Q*distributed in its volume with a charge density*rho*=*kappa*multiplied by*r^alpha*where*kappa*and*alpha*are constants and*r*is the distance from its centre. If the electric field at*r = R/2*is 1/8 times that at*r = R*, find the value of*a.*Answer for Question #6 : 2

We hope that you've had some understanding about the difficulty level of questions from IIT JEE 2009. However we'd like to point out that the questions appeared previously may be completely different and understanding the fundamentals is always the key to success.

So this was about the Physics paper and coming up next: Mathematics questions from IIT JEE 2009.

Want to solve more of these? Guess what? HashLearn Now offers a free one-month trial this exam season. Sign up before 31st March to avail your free month!

So this was about the Physics paper and coming up next: Mathematics questions from IIT JEE 2009.

Want to solve more of these? Guess what? HashLearn Now offers a free one-month trial this exam season. Sign up before 31st March to avail your free month!

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